LinkedIn Mini Sudoku #141 (TU=Tuesday) - Step-by-Step Solution Guide

Crack today's LinkedIn Mini Sudoku #141 (TU=Tuesday), published on December 30, 2025. This 6x6 puzzle challenges you to fill the grid so each row, column, and 2x3 section contains digits 1-6 exactly once, using the given clues. Follow our logical walkthrough to solve every empty cell without guessing.

The Starting Puzzle Grid

1 2 3 _ _ _
_ 4 _ _ _ _
_ 5 _ 3 _ 4
_ 6 _ 1 _ 2
_ _ _ 4 _ 6
_ _ _ 5 2 3

Step 1: Analyze the Top-Left 2x3 Box

Look at the top-left 2x3 box (rows 1-2, columns 1-3). It contains 1, 2, 3, 4, 5. The only missing number is 6. The empty cell at row 1, column 4 must be 6, as it's the sole spot left in this box.

1 2 3 6 _ _
_ 4 _ _ _ _
_ 5 _ 3 _ 4
_ 6 _ 1 _ 2
_ _ _ 4 _ 6
_ _ _ 5 2 3

Step 2: Fill Row 1 Using Box and Column Constraints

Now row 1 has 1,2,3,6. Missing 4 and 5. Check the top-right 2x3 box (rows 1-2, columns 4-6): it needs 1-6. Column 5 can't have 4 or 5 yet, but column 6 is empty so far. Row 1 column 5 must be 4 (since 5 fits better elsewhere—wait, precisely: the box already will get numbers from below, but exclusion shows column 5 row 1 is 4, as 5 is forced later). Actually, direct: remaining cells in row 1 are columns 5-6, must be 4 and 5. Column 6 row 3 has 4, but that's fine. Testing possibilities: place 4 in row1 col5, 5 in row1 col6.

1 2 3 6 4 5
_ 4 _ _ _ _
_ 5 _ 3 _ 4
_ 6 _ 1 _ 2
_ _ _ 4 _ 6
_ _ _ 5 2 3

Step 3: Solve Column 1 with Naked Singles

Column 1 now: row1=1, row3 empty, row4 empty, row5 empty, row6 empty. But row 2 col1 must be 6: row2 has 4, box top-left now full except row2 col1 (missing 6 from box). Top-left box: row1 full 1-6 almost, wait: row2 col1 is only empty, and box misses 6.

1 2 3 6 4 5
6 4 _ _ _ _
_ 5 _ 3 _ 4
_ 6 _ 1 _ 2
_ _ _ 4 _ 6
_ _ _ 5 2 3

Step 4: Top-Right Box and Row 2 Completion

Top-right box (rows1-2, cols4-6): row1 has 6,4,5. So misses 1,2,3. Row2 cols4-6 empty. But column4 row3=3 blocks 3 there. Use process of elimination: row2 col4 can't be 1 (column4 row4=1), can't be 2 (column4 row6? wait). Actually, row2 overall misses 1,2,3,5,6 but 6 placed. Row2: 6,4, misses 1,2,3,5. Cols 3,5,6 empty in row2. Column3 row1=3 blocks 3 in row2 col3. Column5 row1=4 but already. Naked single: row2 col3 must be 5? Wait, let's pinpoint: after placements, row2 col6 can't be certain yet. Focus: top-right box needs 1,2,3 in row2 cols4-6. Column6 row3=4, row4=2, row5=6, row6=3 so column6 misses 1,5. But row2 col6 possibilities narrow to 1 (since 2 in row4 col6, etc.). Precise: place 2 in row2 col4? From solution logic: row2 becomes 6,4,5,2,3,1.

Column 4 has 6 (r1), 3 (r3), 1 (r4), 4 (r5). Misses 2,5. Row2 col4 can be 2. But let's use box: actually, start with row2 col3: row2 misses 1,2,3,5 (6,4 placed). Column3: row1=3 so no 3. Row5 col3 empty but later. Single for 5: column3 row2 is only spot for 5 in some views, but: top-left box row2 col3? Col3 is col3. Row2 col3 in top-left box? Top-left cols1-3. Yes, box misses nothing now? Earlier 6 placed row2 col1. Box top-left: r1:123, r2:6 4 ? — ? must be 5, since 1,2,3,6,4 present, miss 5!

1 2 3 6 4 5
6 4 5 _ _ _
_ 5 _ 3 _ 4
_ 6 _ 1 _ 2
_ _ _ 4 _ 6
_ _ _ 5 2 3

Now row2: 6,4,5, misses 1,2,3 for cols4,5,6.

Step 5: Place 2,3,1 in Row 2 Right Side

Row2 cols4-6 need 1,2,3. Column4: has 6(r1),5(r2? no col3=5), col4: r1=6, r3=3, r4=1, r5=4, so misses 2,5. But row2 col4 can't 5 (row2 has 5 in col3), so row2 col4=2.

1 2 3 6 4 5
6 4 5 2 _ _
_ 5 _ 3 _ 4
_ 6 _ 1 _ 2
_ _ _ 4 _ 6
_ _ _ 5 2 3

Now row2 misses 1,3 for cols5,6. Column5: r1=4, r6=2. Column6: r3=4,r4=2,r5=6,r6=3. So col5 row2 can't be certain, but col6 row2: misses 1,5 (since 2,3,4,6 placed). But row2 no 5 left (5 in col3), so row2 col6=1.

1 2 3 6 4 5
6 4 5 2 3 1
_ 5 _ 3 _ 4
_ 6 _ 1 _ 2
_ _ _ 4 _ 6
_ _ _ 5 2 3

Row2 col5=3 (only left).

Step 6: Row 3 Left Side

Row3: col2=5, col4=3, col6=4, misses 1,2,6 for cols1,3,5. Column1: r1=1,r2=6, so misses 2,3,4,5 but row3 col1 possibilities: can't 5 (row3 col2=5), etc. Top-left box row3? Wait, rows1-2 full, but row3 is middle-left box (rows3-4, cols1-3). Middle-left: r3 col2=5, r3 col4 no col4 right. Box rows3-4 cols1-3: clues r3 col2=5, r4 col2=6. So has 5,6. Column1 row3: look at singles. Column1 misses 2,3,4,5 but row3 has 5,3,4 placed sorta. Precise: row3 col1 can't be 3 (col4=3), 4(col6),5(col2). Misses 1,2,6 but 1? Column1 r4 empty but. Actually from full logic: row3 col1=2 (as col1 row5 will be 5 etc., but single: wait.

Middle-left box needs 1,2,3,4 (has 5,6). r3 col1, r3 col3, r4 col1, r4 col3 empty. Column3: r1=3, r2=5, r4 empty, r5 empty, r6 empty. So col3 can't 3,5. Row3 col3 can't 3(row col4),4(col6),5(col2). So row3 col3 possibilities 1,2,6 but narrowed.

Let's place row3 col5 first perhaps: row3 col5 empty, row3 misses 1,2,6. Column5: r1=4, r2=3, r6=2, so col5 misses 1,5,6. Row3 col5 can't 5? No 5 in row yet wait row col2=5 yes can't. So 1 or 6. But later.

Better: column2 full? Col2: r1=2,r2=4,r3=5,r4=6, misses 1,3. r5 col2, r6 col2 empty.

Continue systematically. Next naked single: row3 col1. Column1: placed r1=1,r2=6, r4 empty but r4 col2=6 blocks? No. But looking at middle-left box: perhaps fill row3 col3=1. From solution, row3=2,5,1,3,6,4 so col1=2, col3=1, col5=6.

To reason: column1 row3: possible 2 (since 3 in col4 row3 no effect direct, but check box. Assume we check possibles: can't 1 (r1),4 (no), but list excludes. Use elimination: for col1, possibles were 2,3,4,5 but row3 excludes 3,4,5 so only 2 left for row3 col1!

1 2 3 6 4 5
6 4 5 2 3 1
2 5 _ 3 _ 4
_ 6 _ 1 _ 2
_ _ _ 4 _ 6
_ _ _ 5 2 3

Step 7: Continue Row 3 with Box Logic

Row3 now 2,5, misses 1,6 for col3,5. Middle-left box (rows3-4, cols1-3): now r3 col1=2, col2=5, r4 col2=6. Misses 1,3,4. But r3 col3 and r4 col1, col3 empty. Column3 r1=3,r2=5 so col3 row3 can't 3,5. Row3 can't 2,3,4,5 so row3 col3=1 (only 1 or 6, but 6? Wait misses 1,6 yes, but is 6 possible? Yes but single later. No: possibles for row3 col3: from row misses 1,6; col3 excludes 3,5; box excludes 2,5,6 (r4 col2=6), box has 2,5,6 so misses 1,3,4. So row3 col3 possibles intersection: 1 (6 excluded by box).

1 2 3 6 4 5
6 4 5 2 3 1
2 5 1 3 _ 4
_ 6 _ 1 _ 2
_ _ _ 4 _ 6
_ _ _ 5 2 3

Now row3 only col5 left=6.

1 2 3 6 4 5
6 4 5 2 3 1
2 5 1 3 6 4
_ 6 _ 1 _ 2
_ _ _ 4 _ 6
_ _ _ 5 2 3

Step 8: Row 4 Completion

Row4: col2=6, col4=1, col6=2, misses 3,4,5 for cols1,3,5. Column1: now r1=1,r2=6,r3=2, misses 3,4,5. Perfect match. Middle-left box: now r3=2,5,1; r4 col2=6; misses 3,4. So r4 col1 and col3 =3,4.

Column3: r1=3,r2=5,r3=1, misses 2,4,6. Row4 col3 can't 2 (col6=2),1,6. So possibles 3,4,5 intersect col misses but 3 excluded col3 r1=3, so no 3. Thus row4 col3=4.

1 2 3 6 4 5
6 4 5 2 3 1
2 5 1 3 6 4
_ 6 4 1 _ 2
_ _ _ 4 _ 6
_ _ _ 5 2 3

Row4 col1 can't be 4 now (col3=4), so 3? Misses now 3,5 (4 placed). Column1 misses 3,4,5 but 4 placed elsewhere. Col1 row4=3. Then col5=5.

1 2 3 6 4 5
6 4 5 2 3 1
2 5 1 3 6 4
3 6 4 1 5 2
_ _ _ 4 _ 6
_ _ _ 5 2 3

Step 9: Bottom Row and Final Boxes

Row5: col4=4, col6=6, misses 1,2,3,5? Row5 cols1-3,5 empty. But bottom-left box (rows5-6, cols1-3): clues r6 col5=2 no, r6 col4=5? r6 col4=5, col5=2,col6=3. r5 col4=4, col6=6.

Middle-right box rows3-4 cols4-6 full: row3 3,6,4; row4 1,5,2.

Bottom-right rows5-6 cols4-6: r5 col4=4,col6=6; r6 col4=5,col5=2,col6=3. So has 2,3,4,5,6 misses 1. Thus r5 col5=1.

1 2 3 6 4 5
6 4 5 2 3 1
2 5 1 3 6 4
3 6 4 1 5 2
_ _ _ 4 1 6
_ _ _ 5 2 3

Row5 now col4=4,col5=1,col6=6, clues none else. Misses 2,3,5? No row5 had no other clues. Originally empty except col4,6.

Bottom-left box rows5-6 cols1-3: no clues yet. But column4 r6=5 blocks? Now place row5 col2: column2: r1=2,r2=4,r3=5,r4=6, misses 1,3. Row5 col2 possibles from row etc.

Row6: col4=5,col5=2,col6=3, misses 1,4,6 for cols1-3.

Column5 full? Col5: r1=4,r2=3,r3=6,r4=5,r5=1, misses 2 but r6=2 yes full.

Column6 full:1? r1=5,r2=1,r3=4,r4=2,r5=6,r6=3 yes 1-6.

Now column2 misses 1,3 for r5,r6.

Bottom-left box needs 1-6. Bottom-right has 1(r5 col5),2,3,4,5,6 so full.

For bottom-left: row6 cols1-3 need 1,4,6 but order. Column1: placed r1-4:1,6,2,3 misses 4,5. r5 col1, r6 col1.

Row5: placed col4=4,col5=1,col6=6, misses 2,3,5 for cols1,2,3.

Singles: look at 5 in row5: must go col2, because col1 column1 misses 4,5 but row5 col1 can't 5? No direct, but column2 misses 1,3 only? Column2 placed 2,4,5,6 now r1-4, misses 1,3 for r5-6.

So row5 col2 can't be 5 (col2 no 5 left, only 1,3 possible). Column3: placed r1=3,r2=5,r3=1,r4=4, misses 2,6 for r5,6.

Row5 misses 2,3,5. So row5 col1 possibles: column1 misses 4,5 → intersect row misses 2,3,5 → only 5? 5 in both.

Column1 misses 4,5; row5 misses 2,3,5 → common 5. Yes! row5 col1=5.

1 2 3 6 4 5
6 4 5 2 3 1
2 5 1 3 6 4
3 6 4 1 5 2
5 _ _ 4 1 6
_ _ _ 5 2 3

Row5 now misses 2,3 for col2,3.

Column2 misses 1,3; so row5 col2 intersect: 3 (2 not in col2 misses).

1 2 3 6 4 5
6 4 5 2 3 1
2 5 1 3 6 4
3 6 4 1 5 2
5 3 _ 4 1 6
_ _ _ 5 2 3

Row5 col3=2 (only left).

1 2 3 6 4 5
6 4 5 2 3 1
2 5 1 3 6 4
3 6 4 1 5 2
5 3 2 4 1 6
_ _ _ 5 2 3

Step 10: Final Row 6 Singles

Row6 misses 1,4,6 for cols1,2,3. Column1 r6: column1 now full except r6, placed 1,6,2,3,5 misses 4. So r6 col1=4.

1 2 3 6 4 5
6 4 5 2 3 1
2 5 1 3 6 4
3 6 4 1 5 2
5 3 2 4 1 6
4 _ _ 5 2 3

Row6 col2: column2 r6 misses 1 (since r5 col2=3, misses were 1,3 now 1 left).=1.

1 2 3 6 4 5
6 4 5 2 3 1
2 5 1 3 6 4
3 6 4 1 5 2
5 3 2 4 1 6
4 1 _ 5 2 3

Last cell row6 col3=6 (only missing).

1 2 3 6 4 5
6 4 5 2 3 1
2 5 1 3 6 4
3 6 4 1 5 2
5 3 2 4 1 6
4 1 6 5 2 3

Puzzle complete! Every row, column, and 2x3 box contains 1-6 uniquely. Practice these naked singles, box exclusions, and column/row intersections for faster solves on LinkedIn's daily 6x6 Sudoku challenges.