LinkedIn Mini Sudoku #156 Boomerangs: Step-by-Step Solution Guide

Crack today's LinkedIn Mini Sudoku #156 Boomerangs published on January 14, 2026. This 6x6 logic puzzle challenges you to fill the grid using clues, ensuring each row, column, and 2x3 box contains digits 1-6 exactly once. Follow this detailed walkthrough to solve it logically—no guessing required. Keywords: LinkedIn Games, Mini Sudoku answer, daily puzzle solution, Boomerangs Sudoku.

Starting Grid Overview

Here's the initial puzzle layout (empty cells shown as blanks):

  1 2 3
     4
    5  
1     
3     
5 2 4    

Full grid for reference:

Step 1: Fill the Top-Left 2x3 Box (Rows 1-2, Columns 1-3)

Look at row 6: It has 5, 2, 4 in columns 1-3. The top-left box (rows 1-2, columns 1-3) can't have 2, 4, or 5 in those columns because they appear in the same columns below.

• Column 1: Can't be 5 (row 6).
• Column 2: Can't be 2 (row 6).
• Column 3: Can't be 4 (row 6).

Row 4 has 1 in column 2, so column 2 can't have 1. Row 5 has 3 in column 1, blocking 3 there.

Row 1, column 1: Possible numbers 1-6, but exclude 3 (row 5), 5 (row 6). Box needs 1-6. Scanning shows only 4 fits—it's missing from column 1 (has 3,5) and available in box.

Place 4 at (1,1).

Step 2: Complete Row 1 Left Side

Now row 1: 4 _ _ 1 2 3

Box has 4; needs 1,2,3,5,6 but 1,2,3 are in columns 4-6, so left side (columns 2-3) must be 5 and 6.

Column 2: Has 1 (row 4), 2 (row 6)—can't be 1,2. Column 3 safe for 5/6.

Column 2 row 1: Only 6 fits (5 blocked elsewhere in analysis). Wait—check column 2: row 6=2, row 4=1. Box needs 5,6 for remaining. Actually, symmetric: place 5 at (1,2), 6 at (1,3).

Confirm: No conflicts. Row 1 now: 4 5 6 | 1 2 3

Step 3: Top Box Row 2 (Columns 1-3)

Top-left box row 2: _ _ _ above 4 5 6 effectively mirrored.

Row 2 column 6=4. Column 1 row 2: Can't be 4 (row 1),3(row5),5(row6). Possibles narrow to 1.

Place 1 at (2,1).

Row 2 now starts 1 _ _ _ _ 4

Column 2 row 2: Can't be 5(row1),1(row4),2(row6),4(col6? no). Box has 4,5,6 row1; 1 col1. Needs 2,3. Column 2 blocks 1,2,5—3 fits.

Place 3 at (2,2), then 2 at (2,3).

Row 2: 1 3 2 | _ _ 4

Step 4: Middle-Left Box (Rows 3-4, Columns 1-3)

Row 3 column 5=5. Row 4 col2=1.

Column 1 row 3/4: Has 4(r1),1(r2),3(r5),5(r6)—only 6 left for col1 row3.

Place 6 at (3,1).

Now middle-left box: row3 col1=6, row4 col2=1.

Row 3: 6 _ _ _ 5 _

Column 3: Has 6(r1),2(r2),4(r6)—blocks 2,4,6. Row3 col3: Box needs remaining after placements.

Narrow: 4 can't (r6 col3), wait—analysis shows 3? Wait, precise: column 3 possibles exclude row1=6, row2=2, row6=4, row? Only 1,3,5 left but 5 in col5 row3 same row. Row3 col3: 4 no—actually 5 blocked row, wait.

Box row3-4 col1-3: col1 row3=6, col2 row4=1. Needs 2,3,4,5.

Continue to singles.

Step 5: Fill Using Singles and Eliminations

Row 3 col3: Check row3 (6,_,_,_,5,_), col3 (6,2,_,_,_,4)—possibles 1,3. Box excludes placed.

Actually, place 3 at (3,3)? No—logic: top-right box row3 col4-6 has 5 in col5, needs others.

Key naked single: Look at row 6 col4-6: blanks, but col4 has 1(r1).

Progress to bottom-left box complete.

• Row 4 col1: Column1 now 4,1,6,?,3,5—all filled? No, row4 col1: excludes 4,1,6,3,5—only 2.

Place 2 at (4,1)? Wait row4: _1__ __

Systematic: After top rows, row5 col2: Column2=5(r1),3(r2),1(r4),2(r6)—only 4,6 left but box.

Step 6: Chain Deductions for Remaining

With top two rows filled: Row1: 45 6123, Row2:13 2__4

Row3 left:6 _ _

Bottom-left box (rows5-6 col1-3):3_ _ |52 4 — has 2,3,4,5; needs 1,6.

Row5 col2/3 blanks. Column2 row5: excludes 5,3,1,2—4 and 6. But row6 col3=4 blocks 4 in col3 row5.

Thus row5 col2=6? Precise chain:

Focus on 5's: Already 5 at (3,5),(6,1). Row3 col6 can't 5 (row).
Column6:4(r2)—etc.

Continue eliminating: Row2 col4: Possibles exclude row2 nums 1,3,2,4; col4 1(r1)—2,3,4,5,6 left? Box top-right: row1 col4-6=123, row2 col6=4, so row2 col4-5 need 5,6.

Col4 row2 can't 1(r1 col4), col5 row2 can't 2(r1 col5). So row2 col4=5, col5=6.

Row2 complete: 1 3 2 5 6 4

Step 7: Middle Rows and Final Fills

Now row3 col2: Column2=5,3,_,1,_,2 — missing 4,6. But row3 col1=6? Earlier (3,1)=6? Confirm placements.

Assuming progressive: After row2 full, row3 col6: Column6=3(r1),4(r2),5(r3? no col5), blanks. Possibles narrow.

Bottom row col4: Look for single in col4: r1=1, r2=5 now, etc.

Key: Row6 col4 must be number not in row6 5,2,4 or col4 1,5(r2)—chain to 3 later.

Middle box row3 col2: Excludes from col2, box mates.

Eventually: Place 4 at (3,2), 3 no—logic leads to row3: 2 4 3 6 5 1 by elimination.

Step 8: Last Boxes and Verification

With upper 3 rows progressing, bottom mirrors somewhat (boomerang theme?).

Row4: After (4,1)=6? Earlier mistake—correct: column1: r1=4,r2=1,r5=3,r6=5; r3=2? Standard solve:

• (4,1): only 6 left in col1.
• Row4 col3: only 5 left, etc.

Row4 becomes 6 1 5 4 3 2.

Row5: 3 6 1 2 4 5—fits all.

Row6 col4-6: only 3 1 6 remain.

Verify all rows, columns, boxes unique 1-6. Puzzle solved!

Stuck? Retry fullest areas first, like top row with 123 clue. Check solution page for visual grid. Share your solve time in comments! #LinkedInMiniSudoku #SudokuSolution #DailyPuzzle #Boomerangs #LinkedInGames